What is (x-(-3))^2+(y-0)^2=sqrt(6)^2 ?

The solution to (x-(-3))^2+(y-0)^2=sqrt(6)^2 is Circle with (a,b)=(-3,0),r=sqrt((\sqrt{6))^2}

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(x-(-3))^2+(y-0)^2=sqrt(6)^2

(x - (- 3))^{2} + (y - 0)^{2} = 6^{2}

(a, b) = (- 3, 0), r = (6)^{2}

Solution steps

(x - (- 3))^{2} + (y - 0)^{2} = (6)^{2}

Rewrite

(x - (- 3))^{2} + (y - 0)^{2} = 6^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = ((6)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = (6)^{2}

(x - 6)^{(2)} + (y + 2)^{(2)} = 5

(x + 4)^{2} + (y + 1)^{2} = 30

x^{2} + y^{2} + 6 x - 8 y = - 24

y^{2} = 1 - 1 x^{2}

(x + 1)^{2} + (y + \frac{15}{8})^{2} = 5

What is (x-(-3))^2+(y-0)^2=sqrt(6)^2 ?
The solution to (x-(-3))^2+(y-0)^2=sqrt(6)^2 is Circle with (a,b)=(-3,0),r=sqrt((\sqrt{6))^2}