What is x^2+2y+y^2=3 ?

The solution to x^2+2y+y^2=3 is Circle with (a,b)=(0,-1),r=2

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x^2+2y+y^2=3

x^{2} + 2 y + y^{2} = 3

(a, b) = (0, - 1), r = 2

Solution steps

x^{2} + 2 y + y^{2} = 3

Rewrite

x^{2} + 2 y + y^{2} = 3

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 1))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, - 1), r = 2

X^{2} + Y^{2} = 3.7 3^{2}

x^{2} - 24 x + y^{2} - 16 y + 208 = 16

y^{2} \leq - x^{2} + 2

x^{2} + y^{2} - 4 x + 2 y + 1 < 0

(x - 4)^{2} + (y + 7)^{2} = 8

What is x^2+2y+y^2=3 ?
The solution to x^2+2y+y^2=3 is Circle with (a,b)=(0,-1),r=2