What is 9x^2-36x+9y^2+6y=-28 ?

The solution to 9x^2-36x+9y^2+6y=-28 is Circle with (a,b)=(2,-1/3),r=1

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9x^2-36x+9y^2+6y=-28

9 x^{2} - 36 x + 9 y^{2} + 6 y = - 28

(a, b) = (2, - \frac{1}{3}), r = 1

Solution steps

9 x^{2} - 36 x + 9 y^{2} + 6 y = - 28

Rewrite

9 x^{2} - 36 x + 9 y^{2} + 6 y = - 28

in the form of the standard circle equation

(x - 2)^{2} + (y - (- \frac{1}{3}))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, - \frac{1}{3}), r = 1

x^{2} + y^{2} - 2 x - 16 y + 29 = 0

(x - 3)^{2} + (y - 8)^{2} = 25

(x - 0)^{2} + (y - 0)^{2} = 36

(x + 0)^{2} + (y + 0)^{2} = 6

(x + 2)^{2} + (y - 2)^{2} = 16

What is 9x^2-36x+9y^2+6y=-28 ?
The solution to 9x^2-36x+9y^2+6y=-28 is Circle with (a,b)=(2,-1/3),r=1