What is (x-17.1)^2+(y-17.1)^2=114 ?

The solution to (x-17.1)^2+(y-17.1)^2=114 is Circle with (a,b)=(17.1,17.1),r=sqrt(114)

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(x-17.1)^2+(y-17.1)^2=114

(x - 17.1)^{2} + (y - 17.1)^{2} = 114

(a, b) = (17.1, 17.1), r = 114

Solution steps

(x - 17.1)^{2} + (y - 17.1)^{2} = 114

Rewrite

(x - 17.1)^{2} + (y - 17.1)^{2} = 114

in the form of the standard circle equation

(x - 17.1)^{2} + (y - 17.1)^{2} = (114)^{2}

Therefore the circle properties are:

(a, b) = (17.1, 17.1), r = 114

4^{2} = x^{2} + y^{2}

x^{2} + y^{2} = 0^{2}

(p + q) 2 = p^{2} + q^{2}

x^{2} + y^{2} - 4 x - 11 y + 21 = 0

(x - 0)^{2} + (y - 0)^{2} = 10

What is (x-17.1)^2+(y-17.1)^2=114 ?
The solution to (x-17.1)^2+(y-17.1)^2=114 is Circle with (a,b)=(17.1,17.1),r=sqrt(114)