What is (p+q)2=p^2+q^2 ?

The solution to (p+q)2=p^2+q^2 is Circle with (a,b)=(1,1),r=sqrt(2)

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(p+q)2=p^2+q^2

(p + q) 2 = p^{2} + q^{2}

(a, b) = (1, 1), r = 2

Solution steps

(p + q) \cdot 2 = p^{2} + q^{2}

Rewrite

(p + q) 2 = p^{2} + q^{2}

in the form of the standard circle equation

(p - 1)^{2} + (q - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

x^{2} + y^{2} - 4 x - 11 y + 21 = 0

(x - 0)^{2} + (y - 0)^{2} = 10

9 x^{2} + 9 y^{2} - 6 x - 24 y = 19

x^{2} + y^{2} + 6 x + 8 y = 9

x^{(2)} + y^{(2)} + 4 x - 6 y - 12 = 0

What is (p+q)2=p^2+q^2 ?
The solution to (p+q)2=p^2+q^2 is Circle with (a,b)=(1,1),r=sqrt(2)