What is x^2-4x+y^2+5y=12 ?

The solution to x^2-4x+y^2+5y=12 is Circle with (a,b)=(2,-5/2),r=(sqrt(89))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-4x+y^2+5y=12

x^{2} - 4 x + y^{2} + 5 y = 12

(a, b) = (2, - \frac{5}{2}), r = \frac{89}{2}

Solution steps

x^{2} - 4 x + y^{2} + 5 y = 12

Rewrite

x^{2} - 4 x + y^{2} + 5 y = 12

in the form of the standard circle equation

(x - 2)^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{89}{2})^{2}

Therefore the circle properties are:

(a, b) = (2, - \frac{5}{2}), r = \frac{89}{2}

(x - 5)^{2} + (y + 3)^{2} = 1

2 (x - 5)^{2} + 2 y^{2} = 8

(x + 15)^{2} + (y + 11)^{2} = 25

3 x^{2} + 6 x + 9 + 3 y^{2} - 18 y + 81 = 108

2 y = y^{2} + (x + 4)^{2}

What is x^2-4x+y^2+5y=12 ?
The solution to x^2-4x+y^2+5y=12 is Circle with (a,b)=(2,-5/2),r=(sqrt(89))/2