What is 2(x-5)^2+2y^2=8 ?

The solution to 2(x-5)^2+2y^2=8 is Circle with (a,b)=(5,0),r=2

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2(x-5)^2+2y^2=8

2 (x - 5)^{2} + 2 y^{2} = 8

(a, b) = (5, 0), r = 2

Solution steps

2 (x - 5)^{2} + 2 y^{2} = 8

Rewrite

2 (x - 5)^{2} + 2 y^{2} = 8

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 2

(x + 15)^{2} + (y + 11)^{2} = 25

3 x^{2} + 6 x + 9 + 3 y^{2} - 18 y + 81 = 108

2 y = y^{2} + (x + 4)^{2}

x^{2} + (y - 7)^{2} = 9

x^{2} + (y - 7)^{2} = 5

What is 2(x-5)^2+2y^2=8 ?
The solution to 2(x-5)^2+2y^2=8 is Circle with (a,b)=(5,0),r=2