What is (x-2)^2+(y+6)^2=25x ?

The solution to (x-2)^2+(y+6)^2=25x is Circle with (a,b)=(29/2 ,-6),r=(5sqrt(33))/2

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(x-2)^2+(y+6)^2=25x

(x - 2)^{2} + (y + 6)^{2} = 25 x

(a, b) = (\frac{29}{2}, - 6), r = \frac{5 33}{2}

Solution steps

(x - 2)^{2} + (y + 6)^{2} = 25 x

Rewrite

(x - 2)^{2} + (y + 6)^{2} = 25 x

in the form of the standard circle equation

(x - \frac{29}{2})^{2} + (y - (- 6))^{2} = (\frac{5 33}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{29}{2}, - 6), r = \frac{5 33}{2}

x^{2} + y^{2} + 6 x - 10 y + 10 = 0

x^{2} + 2 y^{2} + (x - 1)^{2} = 1

(x + 4)^{2} + (y - 1)^{2} - 9 = 17

(x + 4)^{2} + (y + 4)^{2} = 4

(x)^{2} + (y - 2)^{2} = 4

What is (x-2)^2+(y+6)^2=25x ?
The solution to (x-2)^2+(y+6)^2=25x is Circle with (a,b)=(29/2 ,-6),r=(5sqrt(33))/2