What is (x+4)^2+(y-1)^2-9=17 ?

The solution to (x+4)^2+(y-1)^2-9=17 is Circle with (a,b)=(-4,1),r=sqrt(26)

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(x+4)^2+(y-1)^2-9=17

(x + 4)^{2} + (y - 1)^{2} - 9 = 17

(a, b) = (- 4, 1), r = 26

Solution steps

(x + 4)^{2} + (y - 1)^{2} - 9 = 17

Rewrite

(x + 4)^{2} + (y - 1)^{2} - 9 = 17

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 1)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 1), r = 26

(x + 4)^{2} + (y + 4)^{2} = 4

(x)^{2} + (y - 2)^{2} = 4

(x)^{2} + (y - 2)^{2} = 2

x^{2} + y^{2} - 2 y - 6 y - 6 = 0

x^{2} - 6 x + y^{2} + 2 y = - 1

What is (x+4)^2+(y-1)^2-9=17 ?
The solution to (x+4)^2+(y-1)^2-9=17 is Circle with (a,b)=(-4,1),r=sqrt(26)