What is 58=(x-1)^2+(y+5)^2 ?

The solution to 58=(x-1)^2+(y+5)^2 is Circle with (a,b)=(1,-5),r=sqrt(58)

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58=(x-1)^2+(y+5)^2

58 = (x - 1)^{2} + (y + 5)^{2}

(a, b) = (1, - 5), r = 58

Solution steps

58 = (x - 1)^{2} + (y + 5)^{2}

Rewrite

58 = (x - 1)^{2} + (y + 5)^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 5))^{2} = (58)^{2}

Therefore the circle properties are:

(a, b) = (1, - 5), r = 58

x^{2} - 8 x + y^{2} - y + 8 = 0

3 x^{2} + 6 x + 3 y^{2} - 8 y = 48

(x - 1)^{2} + (y - 2)^{2} = \frac{49}{16}

x^{2} + y^{2} - 2 x - 10 y - 29 = 0

- 16 + x^{2} + y^{2} \geq 0

What is 58=(x-1)^2+(y+5)^2 ?
The solution to 58=(x-1)^2+(y+5)^2 is Circle with (a,b)=(1,-5),r=sqrt(58)