What is (x-1)^2+(y-2)^2= 49/16 ?

The solution to (x-1)^2+(y-2)^2= 49/16 is Circle with (a,b)=(1,2),r= 7/4

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(x-1)^2+(y-2)^2= 49/16

(x - 1)^{2} + (y - 2)^{2} = \frac{49}{16}

(a, b) = (1, 2), r = \frac{7}{4}

Solution steps

(x - 1)^{2} + (y - 2)^{2} = \frac{49}{16}

Rewrite

(x - 1)^{2} + (y - 2)^{2} = \frac{49}{16}

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = (\frac{7}{4})^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = \frac{7}{4}

x^{2} + y^{2} - 2 x - 10 y - 29 = 0

- 16 + x^{2} + y^{2} \geq 0

x^{2} + y^{2} - 50 x - 24 y + 669 = 0

(x + \frac{3}{2})^{2} + (y - 1)^{2} = \frac{17}{4}

X^{2} + Y^{2} - 20 X - 35 Y + 28 = 0

What is (x-1)^2+(y-2)^2= 49/16 ?
The solution to (x-1)^2+(y-2)^2= 49/16 is Circle with (a,b)=(1,2),r= 7/4