What is x^2+y^2= 22/3 ?

The solution to x^2+y^2= 22/3 is Circle with (a,b)=(0,0),r=sqrt(22/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2= 22/3

x^{2} + y^{2} = \frac{22}{3}

(a, b) = (0, 0), r = \frac{22}{3}

Solution steps

x^{2} + y^{2} = \frac{22}{3}

Rewrite

x^{2} + y^{2} = \frac{22}{3}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{22}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{22}{3}

x^{2} + y^{2} - 8 x - 6 y = - 21

x^{2} - 14 x + y^{2} - 10 y + 7 = 0

(x - 3)^{2} + (y - 5)^{2} = 9^{2}

x^{2} + (y + \frac{1}{5})^{2} = \frac{9}{25}

58 = (x - 1)^{2} + (y + 5)^{2}

What is x^2+y^2= 22/3 ?
The solution to x^2+y^2= 22/3 is Circle with (a,b)=(0,0),r=sqrt(22/3)