What is 25x^2+25y^2+60y-20x-360=0 ?

The solution to 25x^2+25y^2+60y-20x-360=0 is Circle with (a,b)=(2/5 ,-6/5),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25x^2+25y^2+60y-20x-360=0

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

(a, b) = (\frac{2}{5}, - \frac{6}{5}), r = 4

Solution steps

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

Rewrite

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

in the form of the standard circle equation

(x - \frac{2}{5})^{2} + (y - (- \frac{6}{5}))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{5}, - \frac{6}{5}), r = 4

(x - 2)^{2} + (y + 8)^{2} = 9

(x + 5)^{2} + (y + 3)^{2} = 100

(x + 7)^{2} + (y - 8)^{2} = 27

x^{2} + y^{2} - 6 x + 1 = 0

4 x^{2} + 4 y^{2} - 8 x + 16 y + 4 = 0

What is 25x^2+25y^2+60y-20x-360=0 ?
The solution to 25x^2+25y^2+60y-20x-360=0 is Circle with (a,b)=(2/5 ,-6/5),r=4