What is x^2+y^2+10x-14y-70=0 ?

The solution to x^2+y^2+10x-14y-70=0 is Circle with (a,b)=(-5,7),r=12

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x^2+y^2+10x-14y-70=0

x^{2} + y^{2} + 10 x - 14 y - 70 = 0

(a, b) = (- 5, 7), r = 12

Solution steps

x^{2} + y^{2} + 10 x - 14 y - 70 = 0

Rewrite

x^{2} + y^{2} + 10 x - 14 y - 70 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 7)^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 5, 7), r = 12

(x - 6)^{2} + (y - 3)^{2} = 25

x^{2} + y^{2} - \frac{42}{11} x - \frac{60}{11} y - \frac{164}{11} = 0

x^{2} + y^{2} + 4 x - 6 y - 9 = 0

x^{2} + y^{2} - 20 y + 44 = 0

x^{2} + y^{2} + 6 x - 12 y = 0

What is x^2+y^2+10x-14y-70=0 ?
The solution to x^2+y^2+10x-14y-70=0 is Circle with (a,b)=(-5,7),r=12