What is -y^{(2)}+14y=x^{(2)}-10x+25+49-12.24 ?

The solution to -y^{(2)}+14y=x^{(2)}-10x+25+49-12.24 is Circle with (a,b)=(5,7),r=3.49857…

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-y^{(2)}+14y=x^{(2)}-10x+25+49-12.24

- y^{(2)} + 14 y = x^{(2)} - 10 x + 25 + 49 - 12.24

(a, b) = (5, 7), r = 3.49857 \dots

Solution steps

- y^{2} + 14 y = x^{2} - 10 x + 25 + 49 - 12.24

Rewrite

- y^{2} + 14 y = x^{2} - 10 x + 25 + 49 - 12.24

in the form of the standard circle equation

(x - 5)^{2} + (y - 7)^{2} = 3.49857 \dots^{2}

Therefore the circle properties are:

(a, b) = (5, 7), r = 3.49857 \dots

\frac{x ^{2}}{4} + \frac{z ^{2}}{4} = 1

(x^{2} + 2 x) + (y^{2} - 2 y) = 14

x^{2} + 4 x + y^{2} + 8 y - 5 = 0

x^{2} - 2 x + y^{2} - 15 = 0

(x - (- 1))^{2} + (y - 5)^{2} = 4

What is -y^{(2)}+14y=x^{(2)}-10x+25+49-12.24 ?
The solution to -y^{(2)}+14y=x^{(2)}-10x+25+49-12.24 is Circle with (a,b)=(5,7),r=3.49857…