What is x^2+y^2+12x+14y+85=4 ?

The solution to x^2+y^2+12x+14y+85=4 is Circle with (a,b)=(-6,-7),r=2

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x^2+y^2+12x+14y+85=4

x^{2} + y^{2} + 12 x + 14 y + 85 = 4

(a, b) = (- 6, - 7), r = 2

Solution steps

x^{2} + y^{2} + 12 x + 14 y + 85 = 4

Rewrite

x^{2} + y^{2} + 12 x + 14 y + 85 = 4

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 7))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 7), r = 2

12 x^{2} + 12 y^{2} + 12 x - 24 y + 3 = 0

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

x^{2} + y^{2} - 36 x + 12 y + 80 = 0

(x - 4)^{2} + (y + 1)^{2} = 4

(x + 2)^{(2)} + (y + 3)^{(2)} = 7

What is x^2+y^2+12x+14y+85=4 ?
The solution to x^2+y^2+12x+14y+85=4 is Circle with (a,b)=(-6,-7),r=2