What is 10x^2+10y^2-80x+200y+920=0 ?

The solution to 10x^2+10y^2-80x+200y+920=0 is Circle with (a,b)=(4,-10),r=2sqrt(6)

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10x^2+10y^2-80x+200y+920=0

10 x^{2} + 10 y^{2} - 80 x + 200 y + 920 = 0

(a, b) = (4, - 10), r = 26

Solution steps

10 x^{2} + 10 y^{2} - 80 x + 200 y + 920 = 0

Rewrite

10 x^{2} + 10 y^{2} - 80 x + 200 y + 920 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 10))^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (4, - 10), r = 26

4 (x + 5)^{2} + 4 (y + 4)^{2} - 20 = 0

x^{2} + y^{2} - 2 x + 4 y - 21 = 0

(x - 1)^{2} + (y - 9)^{2} = 15

(x - 3)^{2} + (y - 4)^{2} = 7

169 - x^{2} - y^{2} > 0

What is 10x^2+10y^2-80x+200y+920=0 ?
The solution to 10x^2+10y^2-80x+200y+920=0 is Circle with (a,b)=(4,-10),r=2sqrt(6)