What is (x^2-12x+36)+(y^2-14y+49)-64=0 ?

The solution to (x^2-12x+36)+(y^2-14y+49)-64=0 is Circle with (a,b)=(6,7),r=8

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(x^2-12x+36)+(y^2-14y+49)-64=0

(x^{2} - 12 x + 36) + (y^{2} - 14 y + 49) - 64 = 0

(a, b) = (6, 7), r = 8

Solution steps

x^{2} - 12 x + 36 + y^{2} - 14 y + 49 - 64 = 0

Rewrite

x^{2} - 12 x + 36 + y^{2} - 14 y + 49 - 64 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - 7)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (6, 7), r = 8

x^{2} + y^{2} = 37

(x + 4)^{2} + (y - 5)^{2} = 100

364 + 28 y + y^{(2)} + x^{(2)} = - 26 x

x^{2} + y^{2} = 84

x^{2} + 6 x + y^{2} - 4 y = 12

What is (x^2-12x+36)+(y^2-14y+49)-64=0 ?
The solution to (x^2-12x+36)+(y^2-14y+49)-64=0 is Circle with (a,b)=(6,7),r=8