What is X^2+Y^2+40X-10Y+55=0 ?

The solution to X^2+Y^2+40X-10Y+55=0 is Circle with (a,b)=(-20,5),r=sqrt(370)

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X^2+Y^2+40X-10Y+55=0

X^{2} + Y^{2} + 40 X - 10 Y + 55 = 0

(a, b) = (- 20, 5), r = 370

Solution steps

X^{2} + Y^{2} + 40 X - 10 Y + 55 = 0

Rewrite

X^{2} + Y^{2} + 40 X - 10 Y + 55 = 0

in the form of the standard circle equation

(X - (- 20))^{2} + (Y - 5)^{2} = (370)^{2}

Therefore the circle properties are:

(a, b) = (- 20, 5), r = 370

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x^{2} + y^{2} - 4225 = 0

y 3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

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What is X^2+Y^2+40X-10Y+55=0 ?
The solution to X^2+Y^2+40X-10Y+55=0 is Circle with (a,b)=(-20,5),r=sqrt(370)