What is (x-0.5)^2+(y-7)^2=16.25 ?

The solution to (x-0.5)^2+(y-7)^2=16.25 is Circle with (a,b)=(0.5,7),r=4.03112…

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(x-0.5)^2+(y-7)^2=16.25

(x - 0.5)^{2} + (y - 7)^{2} = 16.25

(a, b) = (0.5, 7), r = 4.03112 \dots

Solution steps

(x - 0.5)^{2} + (y - 7)^{2} = 16.25

Rewrite

(x - 0.5)^{2} + (y - 7)^{2} = 16.25

in the form of the standard circle equation

(x - 0.5)^{2} + (y - 7)^{2} = 4.03112 \dots^{2}

Therefore the circle properties are:

(a, b) = (0.5, 7), r = 4.03112 \dots

x^{2} + y^{2} - 6 x - 12 y + 29 = 0

(x)^{2} + y^{2} = 1

(x - 0)^{2} + (y - 2)^{2} = 2^{2}

x^{2} + y^{2} = 0.75

2 (x - 5)^{2} + 2 y^{2} = 18

What is (x-0.5)^2+(y-7)^2=16.25 ?
The solution to (x-0.5)^2+(y-7)^2=16.25 is Circle with (a,b)=(0.5,7),r=4.03112…