What is (x+3)^2+(y-7)^2=58 ?

The solution to (x+3)^2+(y-7)^2=58 is Circle with (a,b)=(-3,7),r=sqrt(58)

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(x+3)^2+(y-7)^2=58

(x + 3)^{2} + (y - 7)^{2} = 58

(a, b) = (- 3, 7), r = 58

Solution steps

(x + 3)^{2} + (y - 7)^{2} = 58

Rewrite

(x + 3)^{2} + (y - 7)^{2} = 58

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 7)^{2} = (58)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 7), r = 58

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(x)^{2} + (y - 5)^{2} = 4

x^{2} + y^{2} - 10 x + 4 y - 56 = 0

x^{2} + y^{2} = 900

(x - 11)^{2} + (y - 14)^{2} = 64

What is (x+3)^2+(y-7)^2=58 ?
The solution to (x+3)^2+(y-7)^2=58 is Circle with (a,b)=(-3,7),r=sqrt(58)