What is 3x^2+3y^2-39x+63y=189 ?

The solution to 3x^2+3y^2-39x+63y=189 is Circle with (a,b)=(13/2 ,-21/2),r=sqrt(431/2)

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3x^2+3y^2-39x+63y=189

3 x^{2} + 3 y^{2} - 39 x + 63 y = 189

(a, b) = (\frac{13}{2}, - \frac{21}{2}), r = \frac{431}{2}

Solution steps

3 x^{2} + 3 y^{2} - 39 x + 63 y = 189

Rewrite

3 x^{2} + 3 y^{2} - 39 x + 63 y = 189

in the form of the standard circle equation

(x - \frac{13}{2})^{2} + (y - (- \frac{21}{2}))^{2} = (\frac{431}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{13}{2}, - \frac{21}{2}), r = \frac{431}{2}

(x - 2)^{2} + (y + 7)^{2} = 169

x^{2} + y^{2} + 6 x - 8 y + 16 = 0

x^{2} + y^{2} = 972

2 (x - 5)^{2} + 2 y^{2} = 32

(x - 5)^{2} + (y + 3)^{2} = 49

What is 3x^2+3y^2-39x+63y=189 ?
The solution to 3x^2+3y^2-39x+63y=189 is Circle with (a,b)=(13/2 ,-21/2),r=sqrt(431/2)