What is x^2+y^2+20x-10y=-27 ?

The solution to x^2+y^2+20x-10y=-27 is Circle with (a,b)=(-10,5),r=7sqrt(2)

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x^2+y^2+20x-10y=-27

x^{2} + y^{2} + 20 x - 10 y = - 27

(a, b) = (- 10, 5), r = 72

Solution steps

x^{2} + y^{2} + 20 x - 10 y = - 27

Rewrite

x^{2} + y^{2} + 20 x - 10 y = - 27

in the form of the standard circle equation

(x - (- 10))^{2} + (y - 5)^{2} = (72)^{2}

Therefore the circle properties are:

(a, b) = (- 10, 5), r = 72

x^{2} + y^{2} + 2 x + 18 y = - 1

x^{(2)} + y^{(2)} + 2 x + 2 y - 7 = 0

2 x^{2} + 2 y^{2} = 72

x^{2} + 2 x + y^{2} - 6 y = 35

(x + 2)^{2} + (y + 6)^{2} = 4

What is x^2+y^2+20x-10y=-27 ?
The solution to x^2+y^2+20x-10y=-27 is Circle with (a,b)=(-10,5),r=7sqrt(2)