What is x^2+y^2+14x-8y+56=0 ?

The solution to x^2+y^2+14x-8y+56=0 is Circle with (a,b)=(-7,4),r=3

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x^2+y^2+14x-8y+56=0

x^{2} + y^{2} + 14 x - 8 y + 56 = 0

(a, b) = (- 7, 4), r = 3

Solution steps

x^{2} + y^{2} + 14 x - 8 y + 56 = 0

Rewrite

x^{2} + y^{2} + 14 x - 8 y + 56 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 4)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 7, 4), r = 3

(x - 5)^{2} + (y + 2)^{2} = 49

x^{2} + y^{2} = 625

(x + 3) (x + 4) + (y - 4) (y - 3) = 0

(x + 5)^{2} + (y + 8)^{2} = 20

4 x^{2} + 4 y^{2} = 4

What is x^2+y^2+14x-8y+56=0 ?
The solution to x^2+y^2+14x-8y+56=0 is Circle with (a,b)=(-7,4),r=3