What is 49x^2+49y^2-56x+56y-49=0 ?

The solution to 49x^2+49y^2-56x+56y-49=0 is Circle with (a,b)=(4/7 ,-4/7),r= 9/7

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49x^2+49y^2-56x+56y-49=0

49 x^{2} + 49 y^{2} - 56 x + 56 y - 49 = 0

(a, b) = (\frac{4}{7}, - \frac{4}{7}), r = \frac{9}{7}

Solution steps

49 x^{2} + 49 y^{2} - 56 x + 56 y - 49 = 0

Rewrite

49 x^{2} + 49 y^{2} - 56 x + 56 y - 49 = 0

in the form of the standard circle equation

(x - \frac{4}{7})^{2} + (y - (- \frac{4}{7}))^{2} = (\frac{9}{7})^{2}

Therefore the circle properties are:

(a, b) = (\frac{4}{7}, - \frac{4}{7}), r = \frac{9}{7}

x^{2} + 2 x + y^{2} - 2 y + 2 = 5

(x - 4)^{2} + (y - 3)^{2} = 4

(x - 2)^{2} + (y + 7)^{2} = 13

3 x^{2} + 3 y^{2} + 54 x - 36 y - 156 = 0

(- x - 3)^{2} + (y - 2)^{2} = 2^{2}

What is 49x^2+49y^2-56x+56y-49=0 ?
The solution to 49x^2+49y^2-56x+56y-49=0 is Circle with (a,b)=(4/7 ,-4/7),r= 9/7