What is (x-4)^2+(y-4)^2=5 ?

The solution to (x-4)^2+(y-4)^2=5 is Circle with (a,b)=(4,4),r=sqrt(5)

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(x-4)^2+(y-4)^2=5

(x - 4)^{2} + (y - 4)^{2} = 5

(a, b) = (4, 4), r = 5

Solution steps

(x - 4)^{2} + (y - 4)^{2} = 5

Rewrite

(x - 4)^{2} + (y - 4)^{2} = 5

in the form of the standard circle equation

(x - 4)^{2} + (y - 4)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (4, 4), r = 5

4 x^{2} + 4 y^{2} - 4 x + 12 y - 71 = 0

x, x^{2} + Y (x)^{2} = 64

2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 2

x^{2} - 4 x + y^{2} - 9 x + 9 = 0

What is (x-4)^2+(y-4)^2=5 ?
The solution to (x-4)^2+(y-4)^2=5 is Circle with (a,b)=(4,4),r=sqrt(5)