What is (x-5)^{(2)}+(y+7)^{(2)}=50 ?

The solution to (x-5)^{(2)}+(y+7)^{(2)}=50 is Circle with (a,b)=(5,-7),r=sqrt(50)

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(x-5)^{(2)}+(y+7)^{(2)}=50

(x - 5)^{(2)} + (y + 7)^{(2)} = 50

(a, b) = (5, - 7), r = 50

Solution steps

(x - 5)^{2} + (y + 7)^{2} = 50

Rewrite

(x - 5)^{2} + (y + 7)^{2} = 50

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 7))^{2} = (50)^{2}

Therefore the circle properties are:

(a, b) = (5, - 7), r = 50

x^{2} - 16 x + 64 + y^{2} - 16 x = 0

x^{2} + y^{2} + 6 x - 4 y - 4 = 0

(x - 4)^{2} + (y + 3)^{2} = \frac{16}{9}

(x - 5)^{2} + (y + 2)^{2} = 61

4 x^{2} + 4 y^{2} + 24 x - 8 y - 9 = 0

What is (x-5)^{(2)}+(y+7)^{(2)}=50 ?
The solution to (x-5)^{(2)}+(y+7)^{(2)}=50 is Circle with (a,b)=(5,-7),r=sqrt(50)