What is (x-(-3))^2+(y-1)^2=8^2 ?

The solution to (x-(-3))^2+(y-1)^2=8^2 is Circle with (a,b)=(-3,1),r=8

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(x-(-3))^2+(y-1)^2=8^2

(x - (- 3))^{2} + (y - 1)^{2} = 8^{2}

(a, b) = (- 3, 1), r = 8

Solution steps

(x - (- 3))^{2} + (y - 1)^{2} = 8^{2}

Rewrite

(x - (- 3))^{2} + (y - 1)^{2} = 8^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 8

x^{2} + y^{2} - 4 x - 2 y - 5 = 0

2 x^{2} + 2 y^{2} + 2 x - 6 y - 7 = 0

(x - 4)^{2} + (y - 6)^{2} = 8

(x - 4)^{2} + (y - 5)^{2} = 16

16 x^{2} + 16 y^{2} + 96 x + 40 y = 315

What is (x-(-3))^2+(y-1)^2=8^2 ?
The solution to (x-(-3))^2+(y-1)^2=8^2 is Circle with (a,b)=(-3,1),r=8