What is (x-1)^2+(y-4)^2=81 ?

The solution to (x-1)^2+(y-4)^2=81 is Circle with (a,b)=(1,4),r=9

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(x-1)^2+(y-4)^2=81

(x - 1)^{2} + (y - 4)^{2} = 81

(a, b) = (1, 4), r = 9

Solution steps

(x - 1)^{2} + (y - 4)^{2} = 81

Rewrite

(x - 1)^{2} + (y - 4)^{2} = 81

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 9

(x + \frac{1}{7})^{2} + (y - \frac{3}{5})^{2} = \frac{25}{9}

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

9 x^{2} + 9 y^{2} - 12 x + 36 y = 104

4 x^{2} + 40 x + 4 y^{2} - 32 = 5

5 x^{2} + 5 y^{2} - 20 x + 10 y = 20

What is (x-1)^2+(y-4)^2=81 ?
The solution to (x-1)^2+(y-4)^2=81 is Circle with (a,b)=(1,4),r=9