What is 5x^2-20x+5y^2+30y-11=0 ?

The solution to 5x^2-20x+5y^2+30y-11=0 is Circle with (a,b)=(2,-3),r=(2sqrt(19))/(sqrt(5))

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5x^2-20x+5y^2+30y-11=0

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

(a, b) = (2, - 3), r = \frac{2 19}{5}

Solution steps

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

Rewrite

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (\frac{2 19}{5})^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = \frac{2 19}{5}

x^{2} + y^{2} + 2 x - 4 y - 31 = 0

x^{2} + 2 x + y^{2} - 8 y + 13 = 0

x^{2} + y^{2} + 6 x + 5 = 0

x^{2} + (y - 12)^{2} = 18

x^{2} + y^{2} + 6 y - 5 = 0

What is 5x^2-20x+5y^2+30y-11=0 ?
The solution to 5x^2-20x+5y^2+30y-11=0 is Circle with (a,b)=(2,-3),r=(2sqrt(19))/(sqrt(5))