What is x^2+y^2+x-2y=16 ?

The solution to x^2+y^2+x-2y=16 is Circle with (a,b)=(-1/2 ,1),r=(sqrt(69))/2

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x^2+y^2+x-2y=16

x^{2} + y^{2} + x - 2 y = 16

(a, b) = (- \frac{1}{2}, 1), r = \frac{69}{2}

Solution steps

x^{2} + y^{2} + x - 2 y = 16

Rewrite

x^{2} + y^{2} + x - 2 y = 16

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - 1)^{2} = (\frac{69}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, 1), r = \frac{69}{2}

x^{2} + y^{2} + 4 x - 8 y + 11 = 0

(x - 6)^{2} + (y - 0)^{2} = 3^{2}

2 x^{2} + 2 y^{2} + 16 x + 12 y + 48 = 0

2 x^{2} + 2 y^{2} - 3 x + y - 1 = 0

3 x^{2} + 3 y^{2} = 3

What is x^2+y^2+x-2y=16 ?
The solution to x^2+y^2+x-2y=16 is Circle with (a,b)=(-1/2 ,1),r=(sqrt(69))/2