What is (x+5/7)^2+(y+2/7)^2=8 ?

The solution to (x+5/7)^2+(y+2/7)^2=8 is Circle with (a,b)=(-5/7 ,-2/7),r=sqrt(8)

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(x+5/7)^2+(y+2/7)^2=8

(x + \frac{5}{7})^{2} + (y + \frac{2}{7})^{2} = 8

(a, b) = (- \frac{5}{7}, - \frac{2}{7}), r = 8

Solution steps

(x + \frac{5}{7})^{2} + (y + \frac{2}{7})^{2} = 8

Rewrite

(x + \frac{5}{7})^{2} + (y + \frac{2}{7})^{2} = 8

in the form of the standard circle equation

(x - (- \frac{5}{7}))^{2} + (y - (- \frac{2}{7}))^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{7}, - \frac{2}{7}), r = 8

x^{2} + y^{2} - 2 x + 4 y - 5 = 0

x^{2} - 12 x + y^{2} - 8 y = 6

(x - 17)^{2} + (y - 5)^{2} = 144

(x - 2)^{2} + (y - 5)^{2} = 49

(x - 5)^{2} + (y - 3)^{2} = 25

What is (x+5/7)^2+(y+2/7)^2=8 ?
The solution to (x+5/7)^2+(y+2/7)^2=8 is Circle with (a,b)=(-5/7 ,-2/7),r=sqrt(8)