What is x^{(2)}+y^{(2)}=1 ?

The solution to x^{(2)}+y^{(2)}=1 is Circle with (a,b)=(0,0),r=1

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x^{(2)}+y^{(2)}=1

x^{(2)} + y^{(2)} = 1

(a, b) = (0, 0), r = 1

Solution steps

x^{2} + y^{2} = 1

Rewrite

x^{2} + y^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

x^{2} + 6 x + y^{2} - 6 y = - 9

(x + i y - 1) ((x - i y) - 1) = 4 (x + i y + 1) (x - i y + 1)

(x + 3)^{2} + (y - 5)^{2} = 81

(2 x^{2} + 8 x) + (2 y^{2}) + 7 = 0

(x - 5)^{2} + (y - 7)^{2} = 16

What is x^{(2)}+y^{(2)}=1 ?
The solution to x^{(2)}+y^{(2)}=1 is Circle with (a,b)=(0,0),r=1