What is (x-5.2)^2+(y+3.7)^2=49 ?

The solution to (x-5.2)^2+(y+3.7)^2=49 is Circle with (a,b)=(5.2,-3.7),r=7

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(x-5.2)^2+(y+3.7)^2=49

(x - 5.2)^{2} + (y + 3.7)^{2} = 49

(a, b) = (5.2, - 3.7), r = 7

Solution steps

(x - 5.2)^{2} + (y + 3.7)^{2} = 49

Rewrite

(x - 5.2)^{2} + (y + 3.7)^{2} = 49

in the form of the standard circle equation

(x - 5.2)^{2} + (y - (- 3.7))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (5.2, - 3.7), r = 7

(x - 4)^{2} + (y - 1)^{2} = 218

2 x^{2} + 2 y^{2} - 14 x + 18 y - 7 = 0

x^{2} + y^{2} = 6 x - 5

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

x^{2} + y^{2} - 14 x - 10 y + 24 = 0

What is (x-5.2)^2+(y+3.7)^2=49 ?
The solution to (x-5.2)^2+(y+3.7)^2=49 is Circle with (a,b)=(5.2,-3.7),r=7