What is 144x^2+144y^2-96x+72y-11=0 ?

The solution to 144x^2+144y^2-96x+72y-11=0 is Circle with (a,b)=(1/3 ,-1/4),r= 1/2

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144x^2+144y^2-96x+72y-11=0

144 x^{2} + 144 y^{2} - 96 x + 72 y - 11 = 0

(a, b) = (\frac{1}{3}, - \frac{1}{4}), r = \frac{1}{2}

Solution steps

144 x^{2} + 144 y^{2} - 96 x + 72 y - 11 = 0

Rewrite

144 x^{2} + 144 y^{2} - 96 x + 72 y - 11 = 0

in the form of the standard circle equation

(x - \frac{1}{3})^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{3}, - \frac{1}{4}), r = \frac{1}{2}

x^{2} + (y - 4)^{2} = 49

x^{2} + y^{2} - x - 10 y + 5 = 0

x^{2} + y^{2} + 5 x - 10 y - 5 = 0

a^{2} - 28 + b^{2} = 7

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{4} = 1

What is 144x^2+144y^2-96x+72y-11=0 ?
The solution to 144x^2+144y^2-96x+72y-11=0 is Circle with (a,b)=(1/3 ,-1/4),r= 1/2