What is x^2+y^2-12x+14y+21=0 ?

The solution to x^2+y^2-12x+14y+21=0 is Circle with (a,b)=(6,-7),r=8

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x^2+y^2-12x+14y+21=0

x^{2} + y^{2} - 12 x + 14 y + 21 = 0

(a, b) = (6, - 7), r = 8

Solution steps

x^{2} + y^{2} - 12 x + 14 y + 21 = 0

Rewrite

x^{2} + y^{2} - 12 x + 14 y + 21 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 7))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (6, - 7), r = 8

(x - 5)^{2} + (y + 2)^{2} = 121

x^{2} + y^{2} + 5 x + 4 y = 46

9 x^{2} + 9 y^{2} - 6 x + 12 y + 4 = 0

x^{2} + y^{2} + 10 x - 16 y - 55 = 0

(x + 8)^{2} + (y + 5)^{2} = 256

What is x^2+y^2-12x+14y+21=0 ?
The solution to x^2+y^2-12x+14y+21=0 is Circle with (a,b)=(6,-7),r=8