What is (x+3)^2+(y+5/4)^2=(11/2)^2 ?

The solution to (x+3)^2+(y+5/4)^2=(11/2)^2 is Circle with (a,b)=(-3,-5/4),r= 11/2

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(x+3)^2+(y+5/4)^2=(11/2)^2

(x + 3)^{2} + (y + \frac{5}{4})^{2} = (\frac{11}{2})^{2}

(a, b) = (- 3, - \frac{5}{4}), r = \frac{11}{2}

Solution steps

(x + 3)^{2} + (y + \frac{5}{4})^{2} = (\frac{11}{2})^{2}

Rewrite

(x + 3)^{2} + (y + \frac{5}{4})^{2} = (\frac{11}{2})^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- \frac{5}{4}))^{2} = (\frac{11}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, - \frac{5}{4}), r = \frac{11}{2}

(x + 3)^{2} + (y + 5)^{2} = 9

(x + 2)^{(2)} + (y - 1)^{(2)} = 16

2 x^{2} + 2 y^{2} - x + y = 1

x^{2} + y^{2} - 4 y = 4

x^{2} + y^{2} - 6 x + 6 y - 7 = 0

What is (x+3)^2+(y+5/4)^2=(11/2)^2 ?
The solution to (x+3)^2+(y+5/4)^2=(11/2)^2 is Circle with (a,b)=(-3,-5/4),r= 11/2