What is 3(x-4)^2+3y^2=12 ?

The solution to 3(x-4)^2+3y^2=12 is Circle with (a,b)=(4,0),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3(x-4)^2+3y^2=12

3 (x - 4)^{2} + 3 y^{2} = 12

(a, b) = (4, 0), r = 2

Solution steps

3 (x - 4)^{2} + 3 y^{2} = 12

Rewrite

3 (x - 4)^{2} + 3 y^{2} = 12

in the form of the standard circle equation

(x - 4)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (4, 0), r = 2

2 x^{2} + 2 y^{2} + 16 x - 8 y = 0

(x + 1)^{2} + (y - 3)^{2} = 5

8 x^{2} + 8 y^{2} - 32 x + 48 y - 16 = 0

4 x^{2} - 2 x + 4 y^{2} - 4 = 0

3 x^{2} + 3 y^{2} - 48 = 0

What is 3(x-4)^2+3y^2=12 ?
The solution to 3(x-4)^2+3y^2=12 is Circle with (a,b)=(4,0),r=2