What is 2x-3x^2-3y^2=-1 ?

The solution to 2x-3x^2-3y^2=-1 is Circle with (a,b)=(1/3 ,0),r= 2/3

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2x-3x^2-3y^2=-1

2 x - 3 x^{2} - 3 y^{2} = - 1

(a, b) = (\frac{1}{3}, 0), r = \frac{2}{3}

Solution steps

2 x - 3 x^{2} - 3 y^{2} = - 1

Rewrite

2 x - 3 x^{2} - 3 y^{2} = - 1

in the form of the standard circle equation

(x - \frac{1}{3})^{2} + (y - 0)^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{3}, 0), r = \frac{2}{3}

x^{2} + y^{2} - 8 x - 12 y + 43 = 0

(x - 3)^{2} + (y - 4)^{2} = 10

(x + 6)^{2} + (y - 3)^{2} = 16

(x + 55)^{2} + (y - 11.5)^{2} = 121

(x - 3)^{2} + (y - 4)^{2} = 36

What is 2x-3x^2-3y^2=-1 ?
The solution to 2x-3x^2-3y^2=-1 is Circle with (a,b)=(1/3 ,0),r= 2/3