What is x^2+y^2+1/2 x+2y+1/16 =0 ?

The solution to x^2+y^2+1/2 x+2y+1/16 =0 is Circle with (a,b)=(-1/4 ,-1),r=1

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x^2+y^2+1/2 x+2y+1/16 =0

x^{2} + y^{2} + \frac{1}{2} x + 2 y + \frac{1}{16} = 0

(a, b) = (- \frac{1}{4}, - 1), r = 1

Solution steps

x^{2} + y^{2} + \frac{1}{2} x + 2 y + \frac{1}{16} = 0

Rewrite

x^{2} + y^{2} + \frac{1}{2} x + 2 y + \frac{1}{16} = 0

in the form of the standard circle equation

(x - (- \frac{1}{4}))^{2} + (y - (- 1))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{4}, - 1), r = 1

x^{2} + y^{2} - 6 x - 8 y - 28 = 0

x^{2} + (y + 4)^{2} = 16

x^{2} + y^{2} + 12 x + 16 y + 75 = 0

x^{2} + y^{2} + 2 x + 4 y - 4091 = 0

(x + 1)^{2} + (y - 5)^{2} = 25

What is x^2+y^2+1/2 x+2y+1/16 =0 ?
The solution to x^2+y^2+1/2 x+2y+1/16 =0 is Circle with (a,b)=(-1/4 ,-1),r=1