What is 3x^2+3y^2+6x+24y=9 ?

The solution to 3x^2+3y^2+6x+24y=9 is Circle with (a,b)=(-1,-4),r=2sqrt(5)

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3x^2+3y^2+6x+24y=9

3 x^{2} + 3 y^{2} + 6 x + 24 y = 9

(a, b) = (- 1, - 4), r = 25

Solution steps

3 x^{2} + 3 y^{2} + 6 x + 24 y = 9

Rewrite

3 x^{2} + 3 y^{2} + 6 x + 24 y = 9

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 4))^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 4), r = 25

(x + 5)^{2} + (y - 4)^{2} = 4

(x - 1)^{2} + y^{2} = 9

(x - 1)^{2} + (y + 4)^{2} = 12

x^{2} + y^{2} - 2 x - 15 + 4 y = 0

(x + 1)^{2} + (y - 5)^{2} = 4

What is 3x^2+3y^2+6x+24y=9 ?
The solution to 3x^2+3y^2+6x+24y=9 is Circle with (a,b)=(-1,-4),r=2sqrt(5)