What is 9x^2+9y^2=16 ?

The solution to 9x^2+9y^2=16 is Circle with (a,b)=(0,0),r= 4/3

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9x^2+9y^2=16

9 x^{2} + 9 y^{2} = 16

(a, b) = (0, 0), r = \frac{4}{3}

Solution steps

9 x^{2} + 9 y^{2} = 16

Rewrite

9 x^{2} + 9 y^{2} = 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{4}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{4}{3}

x^{2} + y^{2} + 4 y - 117 = 0

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} + \frac{5}{2} x + 10 y + 5 = 0

(x - 7)^{2} + (y + 2)^{2} = 100

x^{2} + y^{2} - 14 x - 4 y + 17 = 0

(x - 2)^{2} + (y - 4)^{2} = 17

What is 9x^2+9y^2=16 ?
The solution to 9x^2+9y^2=16 is Circle with (a,b)=(0,0),r= 4/3