What is x^2+y^2-6x+4y=12 ?

The solution to x^2+y^2-6x+4y=12 is Circle with (a,b)=(3,-2),r=5

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x^2+y^2-6x+4y=12

x^{2} + y^{2} - 6 x + 4 y = 12

(a, b) = (3, - 2), r = 5

Solution steps

x^{2} + y^{2} - 6 x + 4 y = 12

Rewrite

x^{2} + y^{2} - 6 x + 4 y = 12

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 5

x^{2} + y^{2} - 8 x - 10 y + 5 = 0

9 x^{2} - 6 x + 9 + 9 y^{2} + 24 y + 144 = 172

x^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1

What is x^2+y^2-6x+4y=12 ?
The solution to x^2+y^2-6x+4y=12 is Circle with (a,b)=(3,-2),r=5