What is x^2+y^2-12x+6y+36=0 ?

The solution to x^2+y^2-12x+6y+36=0 is Circle with (a,b)=(6,-3),r=3

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x^2+y^2-12x+6y+36=0

x^{2} + y^{2} - 12 x + 6 y + 36 = 0

(a, b) = (6, - 3), r = 3

Solution steps

x^{2} + y^{2} - 12 x + 6 y + 36 = 0

Rewrite

x^{2} + y^{2} - 12 x + 6 y + 36 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (6, - 3), r = 3

4 y^{2} + 4 x^{2} - 24 x + 35 = 0

x^{2} + y^{2} + 10 x + 14 y = - 70

x^{2} + y^{2} - 6 x - 4 y - 15 = 0

y^{2} = 7 - x^{2}

(x - 1)^{2} + (y + 3)^{2} - 9 = 0

What is x^2+y^2-12x+6y+36=0 ?
The solution to x^2+y^2-12x+6y+36=0 is Circle with (a,b)=(6,-3),r=3