What is x^2+y^2+8x-10y-1=0 ?

The solution to x^2+y^2+8x-10y-1=0 is Circle with (a,b)=(-4,5),r=sqrt(42)

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x^2+y^2+8x-10y-1=0

x^{2} + y^{2} + 8 x - 10 y - 1 = 0

(a, b) = (- 4, 5), r = 42

Solution steps

x^{2} + y^{2} + 8 x - 10 y - 1 = 0

Rewrite

x^{2} + y^{2} + 8 x - 10 y - 1 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 5)^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 5), r = 42

x^{2} + y^{2} - 2 x - 6 y - 26 = 0

9 - (x^{2} + y^{2}) \geq 0

x^{2} + y^{2} - 4 x + 3 = 0

(x - 2)^{2} + (y - 4)^{2} = 36

(x + 5)^{2} + (y - 3)^{2} = 49

What is x^2+y^2+8x-10y-1=0 ?
The solution to x^2+y^2+8x-10y-1=0 is Circle with (a,b)=(-4,5),r=sqrt(42)