What is 3x^2+3y^2+30x-12y-60=0 ?

The solution to 3x^2+3y^2+30x-12y-60=0 is Circle with (a,b)=(-5,2),r=7

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3x^2+3y^2+30x-12y-60=0

3 x^{2} + 3 y^{2} + 30 x - 12 y - 60 = 0

(a, b) = (- 5, 2), r = 7

Solution steps

3 x^{2} + 3 y^{2} + 30 x - 12 y - 60 = 0

Rewrite

3 x^{2} + 3 y^{2} + 30 x - 12 y - 60 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 2)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 5, 2), r = 7

2 x^{2} + 2 y^{2} - 16 x + 8 y - 10 = 0

x^{2} + x + (p (x)^{2} - 7 p (x)) = 0

4 x^{2} + 4 y^{2} - 32 x + 8 y - 32 = 0

4 x^{2} + 4 y^{2} + 20 x - 32 y = 5

x^{2} + y^{2} - 20 x + 16 y + 128 = 0

What is 3x^2+3y^2+30x-12y-60=0 ?
The solution to 3x^2+3y^2+30x-12y-60=0 is Circle with (a,b)=(-5,2),r=7