What is (x+40)^2+y^2=30 ?

The solution to (x+40)^2+y^2=30 is Circle with (a,b)=(-40,0),r=sqrt(30)

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(x+40)^2+y^2=30

(x + 40)^{2} + y^{2} = 30

(a, b) = (- 40, 0), r = 30

Solution steps

(x + 40)^{2} + y^{2} = 30

Rewrite

(x + 40)^{2} + y^{2} = 30

in the form of the standard circle equation

(x - (- 40))^{2} + (y - 0)^{2} = (30)^{2}

Therefore the circle properties are:

(a, b) = (- 40, 0), r = 30

4 x^{2} + 4 y^{2} - 4 x + 24 y + 37 = 36

x^{2} + y^{2} - 4 x + 10 y + 4 = 0

x^{2} + y^{2} - 8 x + 10 y + 15 = 0

x^{2} + y^{2} - 10 x - 8 y + 25 = 0

(x - 2)^{2} + (y + 9)^{2} = 1

What is (x+40)^2+y^2=30 ?
The solution to (x+40)^2+y^2=30 is Circle with (a,b)=(-40,0),r=sqrt(30)