What is x^2-4x+y^2=5 ?

The solution to x^2-4x+y^2=5 is Circle with (a,b)=(2,0),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-4x+y^2=5

x^{2} - 4 x + y^{2} = 5

(a, b) = (2, 0), r = 3

Solution steps

x^{2} - 4 x + y^{2} = 5

Rewrite

x^{2} - 4 x + y^{2} = 5

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 3

x^{2} + y^{2} - 10 x + 12 y + 25 = 0

(x + 4)^{2} + (y - 3)^{2} = 9

x^{2} + y^{2} - 16 x - 8 y = 0

(\frac{x - 7}{4})^{2} + (\frac{y + 3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 3 x + 4 y + 4 = 0

What is x^2-4x+y^2=5 ?
The solution to x^2-4x+y^2=5 is Circle with (a,b)=(2,0),r=3