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Beliebt Geometry >

x^2+y^2+10x+12y+12=0

Lösung

x^{2} + y^{2} + 10 x + 12 y + 12 = 0

Lösung

(a, b) = (- 5, - 6), r = 7

Schritte zur Lösung

x^{2} + y^{2} + 10 x + 12 y + 12 = 0

Rewrite

x^{2} + y^{2} + 10 x + 12 y + 12 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 6))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 6), r = 7

Graph

Beliebte Beispiele

(x+3)^2+(y-0)^2=16

(x + 3)^{2} + (y - 0)^{2} = 16

x^2+y^2+14x-16y+86=0

x^{2} + y^{2} + 14 x - 16 y + 86 = 0

(x-4)^2+(y+2)^2=4

(x - 4)^{2} + (y + 2)^{2} = 4

2x^2+2y^2+4x-12y+11=0

2 x^{2} + 2 y^{2} + 4 x - 12 y + 11 = 0

a^{2} + b^{2} = 2009