x^2+y^2+8y=3

解答

x^{2} + y^{2} + 8 y = 3

(a, b) = (0, - 4), r = 19

求解步骤

x^{2} + y^{2} + 8 y = 3

将

x^{2} + y^{2} + 8 y = 3

改写为圆标准方程

(x - 0)^{2} + (y - (- 4))^{2} = (19)^{2}

因此圆的性质是:

(a, b) = (0, - 4), r = 19

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

4 x^{2} + 4 y^{2} = 1

4 x^{2} + 4 y^{2} + 6 x - 8 y - 4 = 0

x^{2} + y^{2} - 10 x - 12 y - 3 = 0